AP EAMCET2006PhysicsLaws of Motion
To the free end of spring hanging from a rigid support, a block of mass m is hung and slowly allowed to come to its equilibrium position. Then stretching in the spring is d . If the same block is attached to the same spring and allowed to fall suddenly, the amount of stretching is : (force constant, k )
Options
- Am g k
- B2 d
- Cm g 3 k
- D4 d
Correct answer
B. 2 d
Step-by-step solution
To leave the block, it oscillates in vertical plane. If maximum extension in spring in extreme position of block is x₁ , then Work done by weight of the block = potential energy stored in spring m g x= 1 2 k x^2 x=2 m g k =2 d ( d= m g k )