AP EAMCET202119 Aug 2021Morning ShiftPhysicsMagnetic Properties of MatterActual
The plane of a dip circle is set in the geographic meridian and the apparent dip is δ 1 . It is then set in a vertical plane perpendicular to the geographic meridian. The apparent dip angle is δ 2 . The declination θ at the place is
Options
- Atan − 1 ⁡ tan ⁡ δ 1 tan ⁡ δ 2
- Btan − 1 ⁡ tan ⁡ δ 1 + tan ⁡ δ 2
- Ctan − 1 ⁡ tan ⁡ δ 1 tan ⁡ δ 2
- Dtan − 1 ⁡ tan ⁡ δ 1 − tan ⁡ δ 2
Correct answer
C. tan − 1 ⁡ tan ⁡ δ 1 tan ⁡ δ 2
Step-by-step solution
Apparent dip angle if the plane of a dip circle is set in the geographic meridian, tan δ 1 = tan ϕ cos α ⇒ cos α = tan ϕ tan δ 1           ⋯ 1 Apparent dip angle if the vertical plane perpendicular to the geographic meridian, tan δ 2 = tan ϕ sin α ⇒ sin α = tan ϕ tan δ 2             ⋯ 2 From equations (1) and (2) we have ⇒ sin α cos α = tan α = tan δ 1