AIIMS2016PhysicsLaws of Motion
A body of mass 60 ~kg is suspended by means of three strings P, Q and R as shown in the figure is in equilibrium. The tension in the string P is
Options
- A130.9 ~g ~N
- B60 gN
- C50 ~g ~N
- D103.9 ~g ~N
Correct answer
D. 103.9 ~g ~N
Step-by-step solution
R 60^ =Q=60 ~g ^ 60 ~g aligned & R= 60 ~g 60^ =120 ~g & P=R 60^ =120 ~g 3 2 =103.9 ~g ~N aligned