AIIMS2015PhysicsLaws of Motion
A mass M is tied to the top of two identical poles of height H using massless strings of equal length. The mass is at height h above the ground at equilibrium. If the distance between poles is L the tension in each string will be
Options
- AM g ( L 2 )^2+(H-h)^2 2(H-h)
- BM g L^2+H^2 2(H-h)
- CM g L^2+H^2 2 H
- DM g h^2+L^2 2 L
Correct answer
A. M g ( L 2 )^2+(H-h)^2 2(H-h)
Step-by-step solution
At equilibrium, M g=2 T T= M g 2 Here, = (H-h) (L / 2)^2+(H-h)^2 From equation (i) T= M g (L / 2)^2+(H-h)^2 2(H-h)