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AIIMS 2017
Exam
AIIMS
Year
2017
Subject
Physics
Chapter
Laws of Motion

AIIMS 2017 · Physics · Laws of Motion

Same spring is attached with 2 ~kg, 3 ~kg and 1 ~kg blocks in three...

Same spring is attached with 2 kg,3 kg2 \mathrm{~kg}, 3 \mathrm{~kg} and 1 kg1 \mathrm{~kg} blocks in three different cases as shown in figure. If x1,x2,x3x_1, x_2, x_3 be the extensions in the spring in the three cases, then Same spring is attached with 2 ~kg, 3 ~kg and 1 ~kg blocks in three different cases as shown in figure. If x_1, x_2,

Options

  1. Ax1=0,x3>x2x_1=0, x_3>x_2
  2. Bx1>x2>x3x_1>x_2>x_3
  3. Cx3>x2>x1x_3>x_2>x_1
  4. Dx2>x1>x3x_2>x_1>x_3

Correct answer

D. x2>x1>x3x_2>x_1>x_3

Step-by-step solution

If T1,T2,T3T_1, T_2, T_3 are the tensions in the strings in the three cases, we have T1=2m1m2gm1+m2=2×2×2g(2+2)=2gT2=2×3×2g(3+2)=2.4gT3=2×1×2g(1+2)=1.33g As x∝T and T2>T1>T3∴x2>x1>x3\begin{aligned} & T_1=\frac{2 m_1 m_2 g}{m_1+m_2}=\frac{2 \times 2 \times 2 g}{(2+2)}=2 g \\ & T_2=\frac{2 \times 3 \times 2 g}{(3+2)}=2.4 g \\ & T_3=\frac{2 \times 1 \times 2 g}{(1+2)}=1.33 g \\ & \text{ As } x \propto T \text{ and } T_2>T_1>T_3 \\ & \therefore \quad x_2>x_1>x_3\end{aligned}
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