AIIMS2010PhysicsLaws of Motion
A block of mass m is pulled along a horizontal surface by applying a force at an angle with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is , then the work done by the applied force is
Options
- Am g d +
- Bm g d +
- Cm g d +
- Dm g d -
Correct answer
B. m g d +
Step-by-step solution
Because the block moves with a uniform velocity, the resultant force is zero. Resolving F into horizontal component F and vertical component F , we get aligned & R+F =m g or R=m g-F & Also f= R= (m g-F ) & But F =f & or F = (m g-F ) & or F( + )= m g & F= m g + aligned Work W=F s aligned & W= m g d + & ( s=d) aligned