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AIIMS2010PhysicsLaws of Motion

A block of mass m is pulled along a horizontal surface by applying a force at an angle with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is , then the work done by the applied force is

Options

  1. Am g d +
  2. Bm g d +
  3. Cm g d +
  4. Dm g d -

Correct answer

B. m g d +

Step-by-step solution

Because the block moves with a uniform velocity, the resultant force is zero. Resolving F into horizontal component F and vertical component F , we get aligned & R+F =m g or R=m g-F & Also f= R= (m g-F ) & But F =f & or F = (m g-F ) & or F( + )= m g & F= m g + aligned Work W=F s aligned & W= m g d + & ( s=d) aligned

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