AP EAMCET201923 Apr 2019Morning ShiftPhysicsNuclear PhysicsActual
The energy released when one nucleus of ( ₉₂ U ²³⁵ ) undergoes fission is (188 MeV ). The energy released when (100 ~g ) of ( ₉₂ U ²³⁵ ) undergoes fission is
Options
- A(3.55 10¹² ~J )
- B(7.71 10¹² ~J )
- C(3.55 10¹³ ~J )
- D(7.71 10¹³ ~J )
Correct answer
B. (7.71 10¹² ~J )
Step-by-step solution
Given, energy released, (E₀=188 MeV ) per nucleus fission and mass, (m=100 gm ) As number of nucleus in (100 gm ) of ( ₉₂ U ²³⁵ ) (N= 100 M N_A ) where, (N_A= ) Avogadro number and (M= ) molecular mass ( N= 100 235 6.022 10²³=2.56 10²³ ) nucleus Energy released in fission of one nucleus ( aligned E₀^ & =E₀=188 10^6 1.6 10⁻¹⁹ ~J & =300.8 10⁻¹³ ~J aligned ) So, Energy released in ( N )-nucleus fission, ( aligned & E=E₀^ N=2.5610²³ 300.8 10⁻¹³ ~J & E=7.71 10¹² ~J aligned ) Hence, the correct option is (b).