AP EAMCET201920 Apr 2019Morning ShiftPhysicsNuclear PhysicsActual
In a nuclear reactor the activity of a radioactive substance is (2000 / s ). If the mean life of the products is 50 minutes, then in the steady power generation, the number of radio nuclides is
Options
- A(12 10^5 )
- B(60 10^5 )
- C(90 10^5 )
- D(15 10^5 )
Correct answer
B. (60 10^5 )
Step-by-step solution
Given, nuclear reactor the activity of a radioactive substance, ( d N d t =2000 / s ) and mean-life of the products, ( aligned & =50 ~min & =50 60 sec aligned ) Now, the mean-life of the radioactive substance is inversely proportional to disintegration constant ( ) i.e., ( = 1 = 1 = 1 50 60 per second ) ( ) The rate of decay is proportional to the number of radio nuclides is given as ( aligned & | d N d t | N & | d N d t |= N 2000= 1 50 60 N aligned ) Where, ( ) is a disintegration constant. Putting the given value