The mass defect in a particular nuclear reaction is 0.3 ~g . The amount of energy liberated in kilowatt hour is : (Velocity of light =3 10^8 )

Step-by-step solution

m=0.3 ~g =0.3 10⁻³ ~kg =3 10⁻⁴ ~kg Energy liberated, E= m c^2=3 10⁻⁴ (3 10^8 )^2=3 10⁻⁴ 9 10¹⁶=27 10¹² ~J = 27 10¹² 3.6 10^6 kWh =7.5 10^6 kWh