Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET202521 May 2025Evening ShiftPhysicsOscillationsActual

The kinetic energy of a particle executing simple harmonic motion at a displacement of 3 cm from the mean position is 4 mJ. If the amplitude of the particle is 5 cm, then the maximum force acting on the particle is

Options

  1. A0.25 N
  2. B0.50 N
  3. C0.75 N
  4. D1.25 N

Correct answer

A. 0.25 N

Step-by-step solution

No Solution

Practice Oscillations on Quantrex Academy →

More from Oscillations

Force constant of interatomic bond, in a certain element, is 7.1 Nm⁻¹ . If the atom oscillates in SHM in a certain direction, what is its frequency? Given: Mole weight of the given 2026An object of mass 10g executes SHM along the x -axis with frequency of ( 10 ) Hz. At the point x = 2 cm the object has KE 1.2 J and PE 0.4 J. The amplitude of oscillation is 2026A simple pendulum of length L , mass m and electric charge q on its bob is oscillating with a time period T under uniform gravity which is in the - z direction. Upon applying a uni 2026A sphere and a cube of equal masses on a horizontal frictionless floor, are confined between two vertical walls, as shown in the figure. The cube is attached to the wall by a massl 2026A mass of 1 kg is executing SHM. Its displacement is given by x = 6.0 (100t + /4) cm. What is the maximum kinetic energy? 2026If the displacement of a particle executing simple harmonic motion is given by x =0.5 (125.6 t ) , then the time period of oscillation of the particle is nearly (Here x is displace 2025The amplitude of a damped harmonic oscilator becomes 50 % of its initial value in a time of 12 s. If the amplitude of the oscillator at a time of 36 s is x % of its initial amplitu 2025If the function ^2 t ( t is time in second) represents a periodic motion, then the period of the motion is 2025 Full Oscillations list All AP EAMCET PYQs