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AP EAMCET202423 May 2024Morning ShiftPhysicsOscillationsActual

As shown in the figure, two blocks of masses m₁ and m ₂ are connected to a spring of force constant k . The blocks are slightly displaced in opposite directions to x ₁ , x₂ distances and released. If the system executes simple harmonic motion, then the frequency of oscillation of the system ( ) is

Options

  1. A( 1 m₁ + 1 m₂ ) k^2
  2. B( 1 m₁ + 1 m₂ ) k^2
  3. C( 1 m₁ + 1 m₂ )
  4. D( 1 m₁ + 1 m₂ ) k

Correct answer

D. ( 1 m₁ + 1 m₂ ) k

Step-by-step solution

= m₁ m₂ m₁+m₂ Frequency of oscillation is W = k = k ( ~m ₁ ~m ₂ ~m ₁+ m ₂ ) = ( 1 ~m ₁ + 1 ~m ₂ ) k

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