AP EAMCET202423 May 2024Morning ShiftPhysicsOscillationsActual
A mass M attached to a horizontal spring executes simple harmonic motion with amplitude A₁ . When mass M passes mean position then a smaller mass m is attached to it and both of them together executing simple harmonic motion with amplitude A₂ . Then the value of A₁ A₂ is
Options
- Am^2+M^2 M^2
- Bm+M M^2
- Cm+M M
- Dm+M M
Correct answer
C. m+M M
Step-by-step solution
For SHM , at mean position, F _ net =0 By conservation of momentum, aligned & Mv ₁=(M+m) v₂ & M w₁ A₁=(m+m) w₂ A₂ & M ( k M ) A₁=(M+m) ( k M+m ) A₂ & A₁ A₂ = M+m M aligned