AP EAMCET202422 May 2024Evening ShiftPhysicsOscillationsActual
The relation between the force ( F is newton) acting on a particle executing simple harmonic motion and the displacement of the particle ( y in metre) is 500 ~F + ^2 y=0 . If the mass of the particle is 2 g , the time period of oscillation of the particle is
Options
- A8 s
- B6 s
- C2 s
- D4 s
Correct answer
C. 2 s
Step-by-step solution
500 F+ ^2 y=0 F m + ( ^2 500 ~m ) y =0 a=- ( ^2 500 m ) y ... (i) For SHM, a=- ^2 y ... (ii) Comparing eq(i) and (ii), we get aligned & ^2= ^2 500 ~m 2 ~T = ^2 500 ~m & ~T =2 500 ~m ^2 =2 500 2 10⁻³ =2 ~s aligned