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AP EAMCET202421 May 2024Morning ShiftPhysicsOscillationsActual

A spring of spring constant 200 Nm ⁻¹ is initially stretched by 10 cm from the unstretched position. The work to be done to stretch the spring further by another 10 cm is

Options

  1. A3 J
  2. B6 J
  3. C9 J
  4. D12 J

Correct answer

A. 3 J

Step-by-step solution

k =200 ~N _ m ⁻¹, x ₁=10 ~cm , x ₂=10+10=20 ~cm Work done to stretch the spring, W = 1 2 k ( x ₂^2- x ₁^2 )= 1 2 200 (20^2-10^2 ) 10⁻⁴=3 ~J

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