AP EAMCET202421 May 2024Morning ShiftPhysicsOscillationsActual
The potential energy of a particle of mass 10 g as a function of displacement x is (50 x^2+100 ) J . The frequency of oscillation is
Options
- A10 s⁻¹
- B5 s⁻¹
- C100 s⁻¹
- D50 s⁻¹
Correct answer
D. 50 s⁻¹
Step-by-step solution
m =10 ~gm =10 10⁻³ ~kg , U = (50 x ^2+100 ) J Restoring force, F =- du dx aligned & F =- d dx (50 x ^2+100 ) & ma =-(100 x ) aligned aligned & a =- 100 10 10⁻³ x =-10^4 x =- ^2 x & ^2=10^4 =100 & Frequency, f = 2 = 100 2 = 50 ~s ⁻¹ aligned