AP EAMCET202419 May 2024Evening ShiftPhysicsOscillationsActual
The displacement of a particle executing simple harmonic motion is y= A (2 t + ) m , where t is time in second and is phase angle. At time t=0 , the displacement and velocity of the particle are 2 m and 4 ~ms ⁻¹ . The phase angle, =
Options
- A60^
- B30^
- C45^
- D90^
Correct answer
C. 45^
Step-by-step solution
aligned & For S H M, y=A (2 t+ ) & v=2 A (2 t+ ) At & t=0, y=2 m, v=4 ms⁻¹ aligned 2=a (2 0+ ) = 2 A ...(i) Also, 4=2 ~A (0+ ) = 2 ~A ...(ii) From eqs (i) and (ii), we get = =45^