AP EAMCET202418 May 2024Morning ShiftPhysicsOscillationsActual
For a particle executing simple harmonic motion, match the following statements (conditions) from column I to statements (shapes of graph) in column II
Options
- A(A) - (iv), (B) - (i), (C) - (ii), (D) - (iii)
- B(A) - (iii), (B) - (i), (C) - (ii), (D) - (iv)
- C(A) - (iii), (B) - (ii), (C) - (i), (D) - (iv)
- D(A) - (iv), (B) - (ii), (C) - (i), (D) - (iii)
Correct answer
B. (A) - (iii), (B) - (i), (C) - (ii), (D) - (iv)
Step-by-step solution
For a particle executing SHM, x = A t , v = AW t , a =- A ^2 t v=A 1- ^2 t =A 1- ( x A )^2 = A^2-x^2 At =1, v^2=A^2-x^2 v^2+x^2=A^2 Velocity displacement graph is a circle. Now, a=-A ^2 t Acceleration time graph is sinusoidal Also, a= (A ^2 ) ( x A )=- ^2 x Acceleration displacement graph is straight line Now, v=A t,-a=-A ^2 t ( v A )^2+ ( a - A )^2= ^2 t + ^2 wt =1 v^2 A^2 ^2 + a^2 A^2 ^4 =1 Acceleration - velocity graph is ellipse