Under the action of a force F=-75 y where F is in Newton and y is in meters, an object of mass 3 ~kg executes simple harmonic motion. If the velocity of the object at the mean position is 2.5 ~ms ⁻¹ , the maximum acceleration of the object is

Step-by-step solution

Action of force, F=-75 y Compair with F =- k y k =75 ~N / m Velocity of the object, v=2.5 ~m / s V _ = A aligned & A= V_ =V_ m k & =2.5 3 75 =0.5 ~m aligned Maximum acceleration, a_ = ^2 ~A = k m 0.5= 75 3 0.5=12.5 ~m / s ^2