What is ratio of Bohr magneton to the nuclear magneton?

Magnetic moment associated with electrons orbitting around the nucleus is given in terms of Bohr magneton $\left(\mu_B\right) \mu_B=\frac{e \hbar}{2 m_e} e=$ electronic charge, $m_e=$ electronic mass. In nuclear physics, magnetic moments associated with the spins of protons and neutrons are expressed in nuclear magnetons $\left(\mu_N\right) \mu_N=\frac{e \hbar}{2 m_p}$$\begin{aligned} & m_p=\text{ mass of a proton. } \\ & \Rightarrow \frac{\mu_B}{\mu_N}=\frac{m_p}{m_e}\end{aligned}$$$