Position of a 2 ~kg mass moving along the X -axis is given by x=2 [(2) t] m . Then maximum kinetic energy of the mass in joule is

Step-by-step solution

Position of particle, x=2 (2 t) Velocity of particle, v= d x d t = d d t 2 2 t v=-2 2 t d d t 2 t v=-4 2 t Velocity is maximum when 2 t=1 . Hence maximum kinetic energy of particle is K_ = 1 2 m (v_ )^2 Substituting m=2 ~kg and v_ =-4 ~m / s ; K_ = 1 2 2 (-4)^2=16 ~J