A particle is executing simple harmonic motion with an instantaneous displacement x=A ^2 ( t- 4 ) . The time period of oscillation of the particle is

Step-by-step solution

Given, instantaneous displacement of particle executing SHM. x=A ^2( t-4) x=A [ 1- 2( t-4) 2 ] ( . Since, . ^2 = 1- 2 2 ) x= A 2 [1- (2 t-8)] Here, angular velocity of particle ^ =2 2 T^ =2 2 T T^ = T 2 = 2 2 = ( T= 2 )