The displacement of a simple harmonic motion of amplitude 6 cm when its kinetic energy is equal to its potential energy is

Step-by-step solution

Given, amplitude of oscillation, a = 6 cm Let displacement be x cm. When kinetic energy is equal to potential energy, then array rlrl & 1 2 m ^2 (a^2-x^2 ) & = 1 2 m ^2 x^2 & a^2-x^2 & =x^2 2 x^2=a^2 & 2 x^2 & =36 x^2=18 & & x & =3 2 ~cm array