The scale of a spring balance which can measure from 0 to 15 kg is 0 . 25 m long. If a body suspended from this balance oscillates with a time period 2 π 5 seconds, neglecting the mass of the spring, find the mass of the body suspended.

Step-by-step solution

The spring constant of the spring is, k = F x = 15 × 10 0 . 25 = 600   N   m - 1 Time period of oscillations, T = 2 π m k ⇒ 2 π 5 = 2 π m 600 ⇒ 1 5 = 1 m 600 ⇒ 1 25 = m 600 ⇒ m = 600 25 = 24   kg