A spring is stretched by 0 . 40 m when a mass of 0 . 6 kg is suspended from it. The period of oscillations of the spring loaded by 255 gm and put to oscillations is close to g = 10 m s - 2 -

Step-by-step solution

Using Hooke's law for spring F = - k x When the mass of 0 . 6   kg   is suspended to the spring then spring force will balance the weight of suspended mass to the spring therefore F = m g ⇒ k = F x = m g x = 0 . 6 × 10 0 . 4 = 15   N   m - 1 Time period for the period of oscillation of the string loaded by 255   gm   or   0 . 255   kg is, T = 2 π m k = 2 π 0 . 255 15 = 0 . 82   s