AP EAMCET202022 Sep 2020Evening ShiftPhysicsOscillationsActual

The maximum velocity of a particle performing simple harmonic motion is 6.28 ~cm ~s ⁻¹ . If the length of its path is 8 ~cm , then what is its period?

Options

A2 ~s
B4 ~s
C3 ~s
D1 ~s

Correct answer

B. 4 ~s

Step-by-step solution

In SHM, v_ =6.28 ~cm ~s ⁻¹ Length of path =8 ~cm Amplitude of particle, a= Length of path 2 = 8 2 =4 ~cm aligned & & v_ max & = a & & & =v_ max / a & & & = 6.28 4 rad s ⁻¹ & & 2 T & = 6.28 4 & & T & = 4 2 6.28 = 4 2 3.14 6.28 =4 ~s aligned

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