When a body is in S H M , then match the following. List - I List - II A Velocity is maximum I Acceleration is maximum B KE is 3 4 th of total energy II At mean position C PE is 3 4 th of total energy III At half of the amplitude D Acceleration is maximum IV At 3 2 times the amplitude

Step-by-step solution

In S . H . M . If equation of S . H . M . is given by y = A sin ω t Velocity v = ω A 2 - x 2 And Acceleration a = - ω 2 x Here ω is angular frequency and x is displacement from mean position. From velocity equation we can see that velocity will be max when x = 0 i.e. particle is at mean position. From acceleration equation we can see that acceleration is maximum at when particle is at extreme position i.e. x = A . Kinetic energy is 1 2 m v 2 = m ω 2 2 A 2 - x 2 Hence, Kinetic energy will be