One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance x 0 , from the block. The spring is then compressed by 2 x 0 and released. The time taken by the block to strike the other wall is

Step-by-step solution

Given, Maximum compression A = 2 x 0 Distance of block from wall x = x 0 Mass of block = m   kg Since initially block is at extreme position, its equation will be- x = A sin   ω t + π 2 = 2 x 0   cos   ω t When block hit the wall, its position will be x = - x 0 Put this value in equation of SHM - - x 0 = 2 x 0   cos   ω t ⇒     cos   ω t = - 1 2 = cos 2 π 3 ⇒     ω t = 2 π 3 For given SHM - ⇒   &#16