The displacement of a particle of mass 2 ~g executing SHM is given by y=5 (4 t+ 3 ) . Here, y is in metres and t is in seconds. The kinetic energy of the particle, when t= T 4 is

Step-by-step solution

gathered Given, y=5 (4 t+ 3 ) =4 and so T= 2 4 = 2 ~s t= [ T 4 = 8 ~s . Velocity = d y d t =20 (4 t+ 3 ) gathered Velocity at t= 8 s is aligned v & =20 (4 8 + 3 )=20 150^ & =-20 30^ =- 20 3 2 ~ms ⁻¹ aligned KE of particle is K= 1 2 m v^2= 1 2 2 1000 100 3=0.3 ~J