AP EAMCET2016PhysicsOscillations
A particle is executing simple harmonic motion with an amplitude of 2 ~m . The difference in the magnitudes of its maximum acceleration and maximum velocity is 4 . The time-period of its oscillation and its velocity when it is 1 m away from the mean position are respectively
Options
- A2 ~s , 2 3 ~ms ⁻¹
- B7 22 ~s , 4 3 ~ms ⁻¹
- C22 7 ~s , 2 3 ~ms ⁻¹
- D44 7 ~s , 4 3 ~ms ⁻¹
Correct answer
C. 22 7 ~s , 2 3 ~ms ⁻¹
Step-by-step solution
As per question, aligned & | A ^2 |-| A |=4 [ A =2 ~m ] & 2 ^2-2 -4=0 & =2 rad / s 2 T =2 & T = = 22 7 s aligned Velocity, v= A^2-y^2 =2 (2)^2-(1)^2 =2 4-1 =2 3 ~ms ⁻¹