AP EAMCET2015PhysicsOscillations
The amplitude of a simple pendulum is 10 ~cm . When the pendulum is at a displacement of 4 ~cm from the mean position, the ratio of kinetic and potential energies at that point is
Options
- A5.25
- B2.5
- C4.5
- D7.5
Correct answer
A. 5.25
Step-by-step solution
aligned & K E = 1 2 m v^2= 1 2 m ^2 (A^2-x^2 ) & P . E = 1 2 k x^2= 1 2 m ^2 x^2 aligned Therefore, the ratio aligned & KE PE = 1 2 m ^2 (A^2-x^2 ) 1 2 m ^2 x^2 KE PE = A ^2- x ^2 x ^2 & 10^2-4^2 4^2 = 84 16 & KE PE = 21 4 =5.25 aligned