A body executes simple harmonic motion under the action of a force F₁ with a time period 4 5 ~s . If the force is changed to F₂ it executes SHM with time period 3 5 ~s . If both the forces F₁ and F₂ act simultaneously in the same direction

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A body executes simple harmonic motion under the action of a force F₁ with a time period 4 5 ~s . If the force is changed to F₂ it executes SHM with time period 3 5 ~s . If both the forces F₁ and F₂ act simultaneously in the same direction on the body, its time period in seconds is

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Correct answer: A. 12 25

If both force acts simultaneously, then time period T=t₁ t₂ . = 4 5 3 5 = 12 25 sec

A body executes simple harmonic motion under the action of a force F₁ with a time period 4 5 ~s . If the force is changed to F₂ it executes SHM with time period 3 5 ~s . If both the forces F₁ and F₂ act simultaneously in the same direction on the body, its time period in seconds is

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