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AP EAMCET202315 May 2023Evening ShiftPhysicsRay OpticsActual

The magnifying power of a telescope with tube length 60 cm is 5 . Then the focal length of its eye piece is

Options

  1. A20 ~cm
  2. B40 ~cm
  3. C30 ~cm
  4. D10 ~cm

Correct answer

D. 10 ~cm

Step-by-step solution

The magnifying power of a telescope is given by aligned & m= f₀ f_e =5 & f₀=5 f_e & f₀+f_e=60 ~cm 5 f_e+f_e=60 & 6 f_e=60 f_e=10 ~cm aligned The focal length of its eye piece, f_e=10 ~cm

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