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AP EAMCET201920 Apr 2019Morning ShiftPhysicsRay OpticsActual

An object is placed (0.1 ~m ) infront of a convex lens of focal length (20 ~cm ) made of a material of refractive index 1.5. The surface of the lens away from the object is silvered. If the radius of curvature of the silvered surface is (22 ~cm ), then the distance of the final image from the silvered surface is

Options

  1. A(10 ~cm )
  2. B(11 ~cm )
  3. C(12 ~cm )
  4. D(13 ~cm )

Correct answer

B. (11 ~cm )

Step-by-step solution

Given, focal length of convex lens, (f=20 ~cm ) object distance, (u=-0.1 ~m =-10 ~cm ) refractive index of material, ( =1.5 ) radius of curvature of silvered surface, (R=22 ~cm ) and focal length of concave mirror, (f_m= -R 2 =-11 ~cm ) Therefore, the power of the mirror, (P_m=- 1 f_m P_m= 1 11 D ) ...(i) Further, focal length of the lens is (20 ~cm ). So, the power of lens, (P_l= 1 20 D ) ...(ii) When the light after passing through the lens will be reflected back by concave mirror through convex lens again then ,

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