Assertion : A planar circular loop of area A and carrying current I...

Magnetic field due to a circular loop carrying current I is given as $B=\frac{\mu_0}{4 \pi} \frac{2 \pi I r^2}{\left(r^2+x^2\right)^{3 / 2}}$ where, $r=$ radius of loop $x=$ distance from centre of loop For large distances, $(x>>r)$, $\therefore \quad B=\frac{\mu_0}{4 \pi} \frac{2 I A}{x^3}=\frac{\mu_0}{4 \pi} \frac{2 M}{x^3}$ where $M=I A=$ magnetic dipole moment of current loop which is equal to the magnetic field due to magnetic dipole. Thus, the current loop can be considered as a magnetic dipole.