A flywheel having moment of inertia 10 ~kg - m ^2 is rotating at 50 rad s ⁻¹ . What amount of work needs to be done in order to bring this flywheel to rest in 10 ~s ?

Step-by-step solution

Given that, moment of inertia, I=10 ~kg m ^2 Initial angular velocity, ₀=50 rad / s Final angular velocity, =0 Time taken to stop wheel, t=10 ~s We know that, work done by torque = change of rotational KE aligned W & = KE =K_f-K_i W & = 1 2 I ^2- 1 2 I ₀^2 W & =0- 1 2 10 (50)^2 & =-12500 ~J aligned So, amount of work done to bring the flywheel to rest is 12500 ~J .