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AP EAMCET202124 Aug 2021Morning ShiftPhysicsRotational MotionActual

A communication satellite of 500 ~kg revolves around the Earth in a circular orbit of radius 4.0 10^7 ~m in the equatorial plane of the Earth from West to East. The magnitude of angular momentum of the satellite is

Options

  1. A0.13 10¹⁴ ~kg ~m ^2 ~s ⁻¹
  2. B1.30 10¹⁴ ~kg ~m ^2 ~s ⁻¹
  3. C0.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹
  4. D2.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹

Correct answer

C. 0.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹

Step-by-step solution

Given that, mass of satellite, m=500 ~kg Radius of orbit, r=4 10^7 ~m Now, the satellite is revolving in equatorial plane so, its time period will be equal to time period of rotation of earth i.e., T=24 ~h . Angular velocity of satellite, = 2 T Now, angular momentum, L=m r^2=m ( 2 T ) r^2 aligned & =500 ( 2 24 3600 ) (4 10^7 )^2 & =0.58 10¹⁴ ~kg m ^2 ~s ⁻¹ aligned

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