AP EAMCET202123 Aug 2021Evening ShiftPhysicsRotational MotionActual
If rotational inertia parameter of a body rolling down a rough inclined plane (of inclination and height h ) without slipping is given by =I_ C M / M R^2 , then time taken by the body to reach the bottom of the inclined plane is given by
Options
- At= 1 (1+ ) 2 h g
- Bt= 1 (1+ ) 2 h g
- Ct= 1 (1- ) 2 h g
- Dt= 1 (1+ ) h g
Correct answer
A. t= 1 (1+ ) 2 h g
Step-by-step solution
Given, mass of body =M Radius =R Angle of inclination = Height of inclined surface =h Also, = I_ CM M R^2 Using, the acceleration produced in body rolling down the inclined plane a= g 1+ I_ CM M R^2 = g 1+ ...(i) By using equation of motion, s=u t+ 1 2 a t^2 where u=0 (initial velocity) t= time taken to reach at bottom. s=0+ 1 2 g (1+ ) t^2 t^2= 2 s(1+ ) g But, from the diagram, h s = s= h Substituting the value of s , we get aligned t & = 2 h(1+ ) g ^2 & = 1 2 h(1+ ) g aligned