AP EAMCET202119 Aug 2021Evening ShiftPhysicsRotational MotionActual
A particle of mass ' m ' is projected with a velocity ' u ' ' making an angle ' θ ' with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height is
Options
- A0
- Bm u sin 2 ⁡ θ cos ⁡ θ 2 g
- C2 m u 2 cos 2 ⁡ θ sin ⁡ θ g
- Dm u 3 sin 2 ⁡ θ cos ⁡ θ 2 g
Correct answer
D. m u 3 sin 2 ⁡ θ cos ⁡ θ 2 g
Step-by-step solution
Angular momentum of the particle, L = m v r ⊥ = m v h ⇒ L = m u cos θ × u 2 sin 2 θ 2 g ⇒ L = m u 3 sin 2 θ cos θ 2 g