Kinetic energy of rotation of a flywheel of radius 2 m , mass 8 kg and angular speed 4 rad s - 1 about an axis perpendicular to its plane and passing through its center is

Step-by-step solution

Given that Mass of wheel m = 8   kg radius r = 2   m Angular speed ω = 4   rad   s - 1 Rotational kinetic energy of wheel k = 1 2 I ω 2 ⇒ k = 1 2 m r 2 2 ω 2 ⇒ k = 1 2 8 × 4 2 4 2 = 128   J