AP EAMCET202021 Sep 2020Evening ShiftPhysicsRotational MotionActual
The centre of a wheel rolling on a plane surface moves with a speed (v₀ ). A particle on the rim of the wheel at the same level as the centre will be moving at a speed
Options
- A0
- B(v₀ )
- C( 2 v₀ )
- D(2 v₀ )
Correct answer
C. ( 2 v₀ )
Step-by-step solution
According to question, speed of the centre of wheel is (v₀ ). Particle is situated on the rim of wheel as shown in Fig. (ii). ( aligned v=r & = (O P)^2+(O M)^2 = R^2+R^2 v & = 2 R aligned ) But (v₀=R ) ...(ii) From Eqs. (i) and (ii), we get (v= 2 v₀ )