AP EAMCET201922 Apr 2019Morning ShiftPhysicsRotational MotionActual
A solid sphere rolls down without slipping on a smooth inclined plane of inclination ( ⁻¹(0.42) ). If the acceleration due to gravity is (10 ~ms ⁻² ), the acceleration of the rolling sphere is
Options
- A(1 ~ms ⁻² )
- B(2 ~ms ⁻² )
- C(3 ~ms ⁻² )
- D(4 ~ms ⁻² )
Correct answer
C. (3 ~ms ⁻² )
Step-by-step solution
Given, inclination of inclined plane, ( = ⁻¹(0.42) =0.42 ) Acceleration due to gravity, (g=10 ~m / s ^2 ) Acceleration of rolling solid sphere on the inclined plane without slipping is given by (a= g 1+ I M R^2 ) where, (I= ) moment of inertia (M= ) mass of sphere (R= ) radius of sphere But ( I= 2 5 M R^2 ) ( aligned a= & g 2 M R^2 = 5 7 g & 1+ 5 M R^2 & = 5 7 10 0.42=3 ~m / s ^2 aligned )