AP EAMCET201823 Apr 2018Evening ShiftPhysicsRotational MotionActual
A particle of mass 15 ~kg is moving with a uniform speed 8 ~ms ⁻¹ in x y -plane along the line 3 y=4 x+10 , then the magnitude of its angular momentum about the origin in kg m ^2 ~s ⁻¹ is ( 53^ = 4 5 )
Options
- A240
- B80
- C120
- D280
Correct answer
A. 240
Step-by-step solution
Angular momentum =m v r₁ =15 8 ( 10 3^2+4^2 )=15 8 2=240 ~kg - m ^2 ~s ⁻¹