AP EAMCET201726 Apr 2017Morning ShiftPhysicsRotational MotionActual
A solid sphere is projected up along an inclined plane of inclination 30^ with the horizontal with a speed of 4 ~ms ⁻¹ . If it rolls without slipping, the maximum distance traversed by it is ........ (g=10 ~ms ⁻² )
Options
- A2.24 m
- B112 m
- C1.12 m
- D22.4 m
Correct answer
A. 2.24 m
Step-by-step solution
Given, u=4 ~ms ⁻¹ a= g 1+ I m R^2 = 10 30 1+ 2 5 = 5 7 5 = 25 7 ~m / s ^2 As v^2=u^2+2 a S |S|= u^2 2 a = 4^2 2 25 7 = 16 7 50 = 112 50 =2.24 ~m