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AIIMS2014PhysicsMotion in Two Dimensions

An arrow is projected into air. Its time of flight is 5 ~s and range 200 ~m . What is the maximum height reached by it? (Take g=10 ~m ~s ⁻² )

Options

  1. A31.25 ~m
  2. B24.5 ~m
  3. C18.25 ~m
  4. D46.75 ~m

Correct answer

A. 31.25 ~m

Step-by-step solution

Given, 5= 2 u g or u g = 5 2 Maximum height = u^2 ^2 2 g = g 2 ( u^2 ^2 g^2 )= g 2 ( 5 2 )^2= 10 2 25 4 =31.25 ~m

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