BITSAT 2017

Exam: BITSAT
Year: 2017
Subject: Chemistry
Chapter: Classification of Elements and Periodicity in Properties

BITSAT 2017 · Chemistry · Classification of Elements and Periodicity in Properties

Two elements A and B have electronegativities 1. 2 and 3. 0...

Two elements $A$ and $B$ have electronegativities $1. 2$ and $3. 0$ respectively. The nature of bond between $A$ and $B$ would be

Options

Aionic
Bcovalent
Cco-ordinate
Dmetallic

Correct answer

A. ionic

Step-by-step solution

$∵$ Difference of electronegativity between $( A )$ and $( B )= 3. 0 - 1. 2 = 1. 8$ and, a bond having electronegativity difference greater than $1. 65$ is of ionic nature.

Hence, bond between $( A )$ and $( B )$ would be of ionic nature.&

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