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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Chemistry
Chapter
Ionic Equilibrium

BITSAT 2020 · Chemistry · Ionic Equilibrium

A solution of NH_ 4 Cl and NH_ 3 has pH=8.0. Which of the following...

A solution of NH4Cl\mathrm{NH}_{4} \mathrm{Cl} and NH3\mathrm{NH}_{3} has pH=8.0.\mathrm{pH}=8.0. Which of the following hydroxides may be precipitated when this solution is mixed with equal volume of 0.2 M of metal ion.

Options

  1. ABa(OH)2(Ksp=1.1×10−4)\mathrm{Ba}(\mathrm{OH})_{2} \left(\mathrm{ K}_{\mathrm{sp}}=1.1 \times10^{-4}\right)
  2. BMg(OH)2(Ksp=3.5×10−4)\mathrm{Mg}(\mathrm{OH})_{2} \left(\mathrm{ K}_{\mathrm{sp}}=3.5 \times10^{-4}\right)
  3. CFe(OH)2(Ksp=8.1×10−16)\mathrm{Fe}(\mathrm{OH})_{2} \left(\mathrm{ K}_{\mathrm{sp}}=8.1 \times10^{-16}\right)
  4. DCa(OH)2(Ksp=2.1×10−5)).\mathrm{Ca}(\mathrm{OH})_{2} \left(\mathrm{ K}_{\mathrm{sp}}=2.1 \times10^{-5}\right) ).

Correct answer

C. Fe(OH)2(Ksp=8.1×10−16)\mathrm{Fe}(\mathrm{OH})_{2} \left(\mathrm{ K}_{\mathrm{sp}}=8.1 \times10^{-16}\right)

Step-by-step solution

pH=8,pOH=6;[OH−]=10−6M\mathrm{pH}=8, \mathrm{pOH}=6 ;\left[\mathrm{OH}^{-}\right]=10^{-6} \mathrm{M} Ionic product of Fe(OH)2=0.2×(1×10−6)2=2×10−13>Ksp(=8.1×10−16)\mathrm{Fe}(\mathrm{OH})_{2}=0.2 \times \left(1 \times 10^{-6}\right)^{2}=2 \times 10^{-13} > \mathrm{K}_{\mathrm{sp}} \left(=8.1 \times10^{-16}\right)
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