Given pH of a solution ' A ' is ' 3 ' and it is mixed with another solution ' B ' having pH ' 2 ' . If both solutions are mixed, the resultant pH of the solution will be (Assume concentration and volume remain unchanged after mixing of individual solution)

Step-by-step solution

Given that, pH of solution A = 3 H + of A = 10 - 3   M and, pH of solution B = 2 H + of B = 10 - 2   M Thus, total H + are = 10 - 3 + 10 - 2 = 1 . 1 × 10 - 3   M ∴   pH final = - log H + = - log 1 . 1 × 10 - 3 = 3 - log 1 . 1 = 3 - 1 . 04 = 1 . 9 Therefore, the resultant pH of the solution will be 1 . 9