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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Chemistry
Chapter
Ionic Equilibrium

BITSAT 2012 · Chemistry · Ionic Equilibrium

The pOH value of a solution whose hydroxide ion concentration is...

The pOH value of a solution whose hydroxide ion concentration is 6.2×10−9mol/6.2 \times 10^{-9} \mathrm{ mol} / litre is

Options

  1. A8.21
  2. B6.21
  3. C7.75
  4. D7.21

Correct answer

A. 8.21

Step-by-step solution

−log⁡(OH)=pOH;−log⁡6.2×10−9=pOH∴pOH=8.21-\log (\mathrm{OH})=\mathrm{pOH} ;-\log 6.2 \times 10^{-9}=\mathrm{pOH}\therefore \mathrm{pOH}=8.21
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