Element 'B' forms ccp structure and 'A' 'occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is :

Step-by-step solution

No. of lattice points = No. of octahedral voids = 1 2 No. of tetrahedral voids in c c p structure No. of atoms of B=4 No. of atoms of A= 1 2 No. of octahedral voids = 1 2 4=2 No. of atoms of O= All tetrahedral voids =2 No. of lattice points =2 4=8 Hence, A: B: O=1: 2: 4 Therefore, the formula of the compound is A B₂ O₄