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BITSAT 2017
Exam
BITSAT
Year
2017
Subject
Chemistry
Chapter
States of Matter

BITSAT 2017 · Chemistry · States of Matter

One moles each of four ideal gases are kept as follows.& I. 5L of...

One moles each of four ideal gases are kept as follows.&

I. 5L5L of gas (A)( A ) at 2atm2atm pressure

II. 2.5L2. 5L of gas (B)( B ) at 2atm2atm pressure

III. 1.25L1. 25L of gas (C)( C ) at 2atm2atm pressure

IV. 2.5L2. 5L of gas (D)( D ) at 2.5atm2. 5atm pressure

Which of the above gases is kept at highest temperature.

Options

  1. AGas (A)( A )
  2. BGas (B)( B )
  3. CGas (C)( C )
  4. DGas (D)( D )

Correct answer

A. Gas (A)( A )

Step-by-step solution

∵∵ For ideals gas

pV=nRTpV = nRT

or T=pVnRT = \dfrac{pV}{nR}

∵n=1=∵ n = 1 = constant

R=0.083=R = 0. 083 = constant

∴T∝PV∴ T ∝ PV

Thus,

The gas that shows highest product of p×Vp \times V, has highest temperature.

for
(A) p×V=2×5=10atmLp \times V = 2 \times 5 = 10atmL

(B) p×V=2×2.5=5atmLp \times V = 2 \times 2. 5 = 5atmL

(C) p×V=2×1.25=2.5atmLp \times V = 2 \times 1. 25 = 2. 5atmL

(D) p×V=2.5×2.5=6.25atmLp \times V = 2. 5 \times 2. 5 = 6. 25atmL

Hence gas (A)( A ) show highest temperature.

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